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12x^2+12x=144
We move all terms to the left:
12x^2+12x-(144)=0
a = 12; b = 12; c = -144;
Δ = b2-4ac
Δ = 122-4·12·(-144)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-84}{2*12}=\frac{-96}{24} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+84}{2*12}=\frac{72}{24} =3 $
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